Technical Contacts
l Technical Information l Warranty
Information
DXF files l MSDS l F.A.Q.
Gast provides unparalleled technical support
to our customers. Our team of trained experts in product and process
technologies are always on call to solve your toughest challenges.
Technical Assistance
Representatives:
Ph: 269-926-6171 Ext: 5404
Warranty Analyst:
Ph: 269-934-1268
Customer Technical Support e-mail: technical.gast@idexcorp.com
Customer Technical Support Fax: 269-927-5727
back to top
Here
is some valuable technical information on
various product Applications.
Air Flotation Table
(To determine the cfm required to float an object)
1. Psi to float the object = weight of object(lbs)/surface
area of bottom of object (square inches)
2. Determine number of holes and size of holes
3. Using the psi determined from #1, go to a chart
showing cfm thru an orifice(hole size), and determine cfm thru each
hole
4. Required total cfm = no. of holes x cfm (for
each hole)
5. From Gast catalog, determine the best
compressor/blower for the application
back to top
Air
Knife
Blower sizing for air knife
Sizing a blower for an air knife application is not a simple
process. The velocity of air required depends on how fast the material
to be dried passes under the air knife. With a blower as an air
source, the higher pressure developed by the blower will increase
the air temperature, resulting in a better drying process. Designing
of equipment should include work to minimized air friction losses
in plumbing connecting the air knife to the blower. It is best to
use a larger pipe size than the air source discharge. The best method
to determine the air consumption of an air knife is to test it.
To increase the airflow exiting an air knife, the pressure must
be increased four times.
Air Knife Facts:
A. To get equal distribution of air across the length of the
air knife, the opening area must be 1 1/2 to 2 times smaller than
the cross sectional area of the knife housing.
B. Different air velocities are required depending on the surface
to be dried. Higher velocities are necessary if liquids tend to
cling to the surface. For proper drying, the velocity may vary from
5000 to 20,000 feet per minute.
C. Higher blower pressure capability may be required to overcome
restriction resulting from plumbing between the blower and the air
knife.
D. The air knife should be located as close to the surface to be
dried as practical.
E. Air Velocity,V(FPM)=3204 times times the square root of pressure (pressure, IN-H2O), this is an approximation
since the knife edge radius or sharpness can change these values
considerably
F. Air Velocity, V=Q(air flow in cfm) divided by A(area of opening
in square feet)
Hot Tub/Tank Aeration
Size of blower to be used depends on the water
depth and the surface area:
Blower Model
|
Depth(inches)
|
Blower Model
|
| |
R4
|
R4P
|
R6
|
|
30"
|
60 sq. ft.
|
90 sq. ft.
|
180 sq. ft.
|
|
36"
|
50 sq. ft.
|
80 sq. ft.
|
175 sq. ft.
|
|
42"
|
45 sq. ft.
|
80 sq. ft.
|
160 sq. ft.
|
|
48"
|
0 sq. ft.
|
75 sq. ft.
|
155 sq. ft.
|
Tank Pump Down Times
An approximation of time can be determined as follows:
t=V/Q (N)
where
t = time in minutes
V= volume to be evacuated in cubic ft
Q= average capacity*
N= 1 for vacuums to 15 in-Hg
2 for vacuums greater than 15 but less than 22.5 in-Hg
3 for vacuums greater than 22.5 but less than 26 in-Hg
* using advertised vacuum curves use the above
formula to calculate time in 5 -hg increments, then add each time
increment to get the total time
note: add a 25% safety factor for system
leakage
back to top
Tank Pump Up Time
An estimated pump up time can
be calculated as follows:
T=V(P2-P1)/P0(Acfm)
Where:
T= time in minutes
V= tank volume in cubic feet (cuft=gallons/7.48)
P0= atmospheric pressure in psia
P1= initial tank pressure in psia
P2= final tank pressure in psia
Acfm= average cfm during pump up
Cubic Feet of Air
Tank Size
|
| Pressure Range |
2
|
12
|
20
|
30
|
60
|
| 0-50 psi |
.84
|
5.4
|
9.1
|
13.6
|
27.2
|
| 0-90 psi |
1.64
|
9.8
|
16.4
|
24.5
|
49.1
|
| 30-50 psi |
.4
|
2.2
|
3.6
|
5.5
|
10.9
|
| 70-90 psi |
.4
|
2.2
|
3.6
|
5.5
|
10.9
|
| 60-90 psi |
.6
|
3.3
|
5.5
|
8.2
|
16.5
|
|
To use chart above:
1. determine pressure range___________
2. determine tank size_________________
3. amount of air required by application__________________
4. cubic feet of air(in pressure range) from chart____________________
5. air flow (in pressure range) of pump of choice______________
average compressor flow between starting pressure and final pressure)
6. "4"/("5"-"3")= minutes ON____________________
7.("5"/"3")/"3" = minutes OFF_________________
Vacuum at different elevations
From catalog performance curves for a specific vacuum
pump, determine the pump's maximum vacuum capability. Use this to
determine what % it is of perfect vacuum at sea level. (Example:
if a pump is capable of 25 in-Hg vacuum at sea level, it's capability
is 83.4% of perfect vacuum [25/29.92]).
Example:
The barometer reading at 5000 ft is 24.9. The maximum vacuum capability
of the 25 in-Hg pump at that altitude is 83.4% of 24.9 in-Hg or
20.8 in-Hg.
|
Altitude(ft)
|
Barometer(in-Hg
|
% Change in Air Density
|
|
0
|
29.2
|
0
|
|
2000
|
27.82
|
-7
|
|
4000
|
25.84
|
-13
|
|
6000
|
23.99
|
-20
|
|
8000
|
22.23
|
-26
|
|
10000
|
20.58
|
-31
|
Performance at different
elevations
A 10% decrease in air density reduces performance
by 10%. For example: If a blower produces 110 cfm at 40 in of water
pressure, with a 10% decrease in air density, it will produce the
same air flow at 90% of 40, or 36 in of water.
back to top
Vacuum Lifting
Theoretical lifting force of a vacuum cup
W=C(P)(14.7)/F(29.92)
Where:
W = force in lbs
C = area of cup (sq in)
P = vacuum level in in-Hg
F = safety factor
Better than choosing the smallest cup that will
work, use the largest possible cup to ease requirements on the vacuum
pump. It is better to use a larger cup than to overwork the vacuum
pump. Use a safety factor of 4 for vertical movement and a safety
factor of 2 for horizontal movement.
Application Notes:
Porous material -- use a smaller size cup unless a very high flow
of air is available
Metal Parts - use six or eight evenly distributed
cups instead of two or three smaller cups which calculations show
should be able to lift the weight of the plate.
Vacuum Hold Down
The maximum hold down force on an object, at standard
atmospheric conditions with a perfect vacuum, is 14.7 psi. The actual
force depends on the vacuum level capability of the vacuum pump,
the barometer in your area, and the surface area of the object that
is in contact with the vacuum. For example, if you were to use a
Gast 0323 oilless model (capable of 25 in-Hg) as the vacuum source
in an area with a standard atmospheric pressure (14.7 psi), the
maximum hold down force would be 12.3 psi (25in-Hg¸2.03).
If the hold down table has four (4) ½" diameter holes,
the maximum hold down pressure would be .196 sq-in x 4(or.79 square
inches) x 12.3 psi or 9.7 psi.
Additional hold down force is required if an object
is being held for fabricating purposes, which may produce side,
or twisting loads. If the hold down table surface is smooth, the
object may tend to move no matter the hold down force. Therefore,
it is recommended that a non-skid hold down table surface be used
if possible. Hold down of a small part may not be possible unless
a limited amount of fabrication is being done to it.
To select the best product for an application,
be aware that a vacuum pump, such as the 0323, is best for use with
materials that air will not easily be drawn through. Blowers, on
the other hand, are best to use with porous materials, since blowers
pull large volumes of air
Air
Flow Through an Orifice
back to top
|